consider three points A, B, C such that d(A,B), d(A,C), and d(B,C) are all integers. we knowwww.ddhw.com -d(A,B) <= d(A,C) - d(B,C) <= d(A,B). that means when A, B are fixed, the choice on C are on a family of hyperbolas (finite number) generated by A and B. now if D is not colinear with A and B, but both d(A,D) and d(C,D) are integers. so C is also on the family of hyperbolas generated by A, D. as we can see, with A, B, D three points fixed, there can be only finite number of points left to choose, which are those points lie on the intersection of two families of hyperbolas. The actual candidates are even less because the distances between them have to be integer too. www.ddhw.com
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