There is no such kind of triangle. Let the length for the triangle to be a, b and c. a^2+b^2=c^2 (a+b)^2=(8-c)^2 ab=8*(4-c) =>c=3 ab=8 And consider a+b=5 =>a^2-5a+8=0 There is no a in real number. |
There ought be 2, with area 1 and 2. Do not want do the calculation. It is just quadratic equations. |
easy |
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