1875 |
It's a linear programming problem. Maximize: x + y Subject to: x/3000 + y/5000 <= 1; x/5000 + y/3000 <= 1. The optimal solution is x = y = 1875. So 3750 is the total milage the tires can last. BTW, I think the unit should be miles instead of meters. Nobody will purchase a tire that lasts only several kilometers :-). |
There is a confusion in your formular. If Y is the total distance the car travelled, then Y = X + 3000(1-X/5000). And Why do you want to minimize it? We should maximize Y instead. |
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